4x^2-36/x^2-3x=4(x+3)/x

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Solution for 4x^2-36/x^2-3x=4(x+3)/x equation: 



4x^2-36/x^2-3x=4(x+3)/x

We move all terms to the left:

4x^2-36/x^2-3x-(4(x+3)/x)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4x^2-3x-36/x^2-(4(x+3)/x)=0

We calculate fractions

We do not support expression: x^3

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